720=2x^2+10x-48

Solution for 720=2x^2+10x-48 equation:

720=2x^2+10x-48

We move all terms to the left:

720-(2x^2+10x-48)=0

We get rid of parentheses

-2x^2-10x+48+720=0

We add all the numbers together, and all the variables

-2x^2-10x+768=0

a = -2; b = -10; c = +768;
Δ = b2-4ac
Δ = -102-4·(-2)·768
Δ = 6244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6244}=\sqrt{4*1561}=\sqrt{4}*\sqrt{1561}=2\sqrt{1561}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{1561}}{2*-2}=\frac{10-2\sqrt{1561}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{1561}}{2*-2}=\frac{10+2\sqrt{1561}}{-4}
$